Base | Representation |
---|---|
bin | 100101100010110000010001… |
… | …0100011011001111000011011 |
3 | 1121022020212120121220210011201 |
4 | 1023011200202203121320123 |
5 | 321241010141420124433 |
6 | 3130202255323535031 |
7 | 126362322301410322 |
oct | 11305404243317033 |
9 | 1538225517823151 |
10 | 330232025161243 |
11 | 96249685088387 |
12 | 3105521908a477 |
13 | 1123599197208a |
14 | 5b7945b2770b9 |
15 | 282a15d3b8a7d |
hex | 12c58228d9e1b |
330232025161243 has 4 divisors (see below), whose sum is σ = 349657438406040. Its totient is φ = 310806611916448.
The previous prime is 330232025161229. The next prime is 330232025161261. The reversal of 330232025161243 is 342161520232033.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-330232025161243 is a prime.
It is not an unprimeable number, because it can be changed into a prime (330232025161223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9712706622373 + ... + 9712706622406.
It is an arithmetic number, because the mean of its divisors is an integer number (87414359601510).
Almost surely, 2330232025161243 is an apocalyptic number.
330232025161243 is a deficient number, since it is larger than the sum of its proper divisors (19425413244797).
330232025161243 is a wasteful number, since it uses less digits than its factorization.
330232025161243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19425413244796.
The product of its (nonzero) digits is 155520, while the sum is 37.
Adding to 330232025161243 its reverse (342161520232033), we get a palindrome (672393545393276).
The spelling of 330232025161243 in words is "three hundred thirty trillion, two hundred thirty-two billion, twenty-five million, one hundred sixty-one thousand, two hundred forty-three".
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