Base | Representation |
---|---|
bin | 1111000001101011111110… |
… | …00000110101010110111001 |
3 | 11022222220120101112010201222 |
4 | 13200311333000311112321 |
5 | 13312340201432124423 |
6 | 154135520011121425 |
7 | 6650205063404000 |
oct | 740657700652671 |
9 | 138886511463658 |
10 | 33043314333113 |
11 | a58a65555a347 |
12 | 3858023143275 |
13 | 1558c81881956 |
14 | 82343aabbc37 |
15 | 3c47ebe893c8 |
hex | 1e0d7f0355b9 |
33043314333113 has 8 divisors (see below), whose sum is σ = 38534477356800. Its totient is φ = 28322840856660.
The previous prime is 33043314333037. The next prime is 33043314333203. The reversal of 33043314333113 is 31133341334033.
It is not a de Polignac number, because 33043314333113 - 212 = 33043314329017 is a prime.
It is a super-2 number, since 2×330433143331132 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33043314333413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48168096353 + ... + 48168097038.
It is an arithmetic number, because the mean of its divisors is an integer number (4816809669600).
Almost surely, 233043314333113 is an apocalyptic number.
It is an amenable number.
33043314333113 is a deficient number, since it is larger than the sum of its proper divisors (5491163023687).
33043314333113 is an frugal number, since it uses more digits than its factorization.
33043314333113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96336193412 (or 96336193398 counting only the distinct ones).
The product of its (nonzero) digits is 104976, while the sum is 35.
Adding to 33043314333113 its reverse (31133341334033), we get a palindrome (64176655667146).
The spelling of 33043314333113 in words is "thirty-three trillion, forty-three billion, three hundred fourteen million, three hundred thirty-three thousand, one hundred thirteen".
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