Base | Representation |
---|---|
bin | 1111000001101100001000… |
… | …01000000101110001011001 |
3 | 11022222220210100221122012011 |
4 | 13200312010020011301121 |
5 | 13312340340412341213 |
6 | 154135532313545521 |
7 | 6650210154525502 |
oct | 740660410056131 |
9 | 138886710848164 |
10 | 33043400121433 |
11 | a58a699a24389 |
12 | 3858047a152a1 |
13 | 1558c9658a880 |
14 | 82344824dba9 |
15 | 3c480478303d |
hex | 1e0d84205c59 |
33043400121433 has 16 divisors (see below), whose sum is σ = 35609558100480. Its totient is φ = 30480724633536.
The previous prime is 33043400121371. The next prime is 33043400121437. The reversal of 33043400121433 is 33412100434033.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-33043400121433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 33043400121395 and 33043400121404.
It is not an unprimeable number, because it can be changed into a prime (33043400121437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 335488288 + ... + 335586766.
It is an arithmetic number, because the mean of its divisors is an integer number (2225597381280).
Almost surely, 233043400121433 is an apocalyptic number.
It is an amenable number.
33043400121433 is a deficient number, since it is larger than the sum of its proper divisors (2566157979047).
33043400121433 is a wasteful number, since it uses less digits than its factorization.
33043400121433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115896.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 33043400121433 its reverse (33412100434033), we get a palindrome (66455500555466).
The spelling of 33043400121433 in words is "thirty-three trillion, forty-three billion, four hundred million, one hundred twenty-one thousand, four hundred thirty-three".
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