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331112241011 = 581356960647
BaseRepresentation
bin1001101000101111101…
…00111101011101110011
31011122122210002121221202
410310113310331131303
520411104213203021
6412035540241415
732631161416346
oct4642764753563
91148583077852
10331112241011
11118473256482
12542089a026b
13252ba76c286
141205119445d
15892dc8aa0b
hex4d17d3d773

331112241011 has 4 divisors (see below), whose sum is σ = 331169207472. Its totient is φ = 331055274552.

The previous prime is 331112240971. The next prime is 331112241017. The reversal of 331112241011 is 110142211133.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 331112241011 - 210 = 331112239987 is a prime.

It is a super-2 number, since 2×3311122410112 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (331112241017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28474511 + ... + 28486136.

It is an arithmetic number, because the mean of its divisors is an integer number (82792301868).

Almost surely, 2331112241011 is an apocalyptic number.

331112241011 is a deficient number, since it is larger than the sum of its proper divisors (56966461).

331112241011 is an equidigital number, since it uses as much as digits as its factorization.

331112241011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56966460.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 331112241011 its reverse (110142211133), we get a palindrome (441254452144).

The spelling of 331112241011 in words is "three hundred thirty-one billion, one hundred twelve million, two hundred forty-one thousand, eleven".

Divisors: 1 5813 56960647 331112241011