Base | Representation |
---|---|
bin | 1001101000101111101… |
… | …11110110110001000011 |
3 | 1011122122211112012002120 |
4 | 10310113313312301003 |
5 | 20411104412000003 |
6 | 412040004415323 |
7 | 32631201030222 |
oct | 4642767666103 |
9 | 1148584465076 |
10 | 331113000003 |
11 | 118473724745 |
12 | 542090a7543 |
13 | 252ba976896 |
14 | 12051310cb9 |
15 | 892dd8a853 |
hex | 4d17df6c43 |
331113000003 has 4 divisors (see below), whose sum is σ = 441484000008. Its totient is φ = 220742000000.
The previous prime is 331112999977. The next prime is 331113000011. The reversal of 331113000003 is 300000311133.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300000311133 = 3 ⋅100000103711.
It is a cyclic number.
It is not a de Polignac number, because 331113000003 - 26 = 331112999939 is a prime.
It is not an unprimeable number, because it can be changed into a prime (331113000203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55185499998 + ... + 55185500003.
It is an arithmetic number, because the mean of its divisors is an integer number (110371000002).
Almost surely, 2331113000003 is an apocalyptic number.
331113000003 is a deficient number, since it is larger than the sum of its proper divisors (110371000005).
331113000003 is a wasteful number, since it uses less digits than its factorization.
331113000003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110371000004.
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 331113000003 its reverse (300000311133), we get a palindrome (631113311136).
The spelling of 331113000003 in words is "three hundred thirty-one billion, one hundred thirteen million, three", and thus it is an aban number.
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