3313102030041 has 4 divisors (see below), whose sum is σ = 4417469373392. Its totient is φ = 2208734686692.

The previous prime is 3313102030039. The next prime is 3313102030061. The reversal of 3313102030041 is 1400302013133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 3313102030041 - 2¹ = 3313102030039 is a prime.

It is a super-3 number, since 3×3313102030041³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3313102030001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 552183671671 + ... + 552183671676.

It is an arithmetic number, because the mean of its divisors is an integer number (1104367343348).

Almost surely, 2^{3313102030041} is an apocalyptic number.

It is an amenable number.

3313102030041 is a deficient number, since it is larger than the sum of its proper divisors (1104367343351).

3313102030041 is a wasteful number, since it uses less digits than its factorization.

3313102030041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1104367343350.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 3313102030041 its reverse (1400302013133), we get a palindrome (4713404043174).

The spelling of 3313102030041 in words is "three trillion, three hundred thirteen billion, one hundred two million, thirty thousand, forty-one".