33131210113 has 4 divisors (see below), whose sum is σ = 33132365568. Its totient is φ = 33130054660.

The previous prime is 33131210023. The next prime is 33131210117. The reversal of 33131210113 is 31101213133.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-33131210113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (33131210117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 533593 + ... + 592438.

It is an arithmetic number, because the mean of its divisors is an integer number (8283091392).

Almost surely, 2^33131210113 is an apocalyptic number.

It is an amenable number.

33131210113 is a deficient number, since it is larger than the sum of its proper divisors (1155455).

33131210113 is a wasteful number, since it uses less digits than its factorization.

33131210113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1155454.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 33131210113 its reverse (31101213133), we get a palindrome (64232423246).

The spelling of 33131210113 in words is "thirty-three billion, one hundred thirty-one million, two hundred ten thousand, one hundred thirteen".