Base | Representation |
---|---|
bin | 11110111010110000… |
… | …101111011011000001 |
3 | 10011200122002202002111 |
4 | 132322300233123001 |
5 | 1020442204013101 |
6 | 23130114415321 |
7 | 2253452165611 |
oct | 367260573301 |
9 | 104618082074 |
10 | 33198110401 |
11 | 13096516785 |
12 | 6525b91541 |
13 | 3190b21811 |
14 | 186d0a0a41 |
15 | ce47a2251 |
hex | 7bac2f6c1 |
33198110401 has 4 divisors (see below), whose sum is σ = 33200025904. Its totient is φ = 33196194900.
The previous prime is 33198110381. The next prime is 33198110423. The reversal of 33198110401 is 10401189133.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 33198110401 - 213 = 33198102209 is a prime.
It is a super-2 number, since 2×331981104012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (33198140401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 931515 + ... + 966496.
It is an arithmetic number, because the mean of its divisors is an integer number (8300006476).
Almost surely, 233198110401 is an apocalyptic number.
It is an amenable number.
33198110401 is a deficient number, since it is larger than the sum of its proper divisors (1915503).
33198110401 is a wasteful number, since it uses less digits than its factorization.
33198110401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1915502.
The product of its (nonzero) digits is 2592, while the sum is 31.
Adding to 33198110401 its reverse (10401189133), we get a palindrome (43599299534).
The spelling of 33198110401 in words is "thirty-three billion, one hundred ninety-eight million, one hundred ten thousand, four hundred one".
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