33200103113 has 4 divisors (see below), whose sum is σ = 33200820240. Its totient is φ = 33199385988.

The previous prime is 33200103091. The next prime is 33200103119. The reversal of 33200103113 is 31130100233.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 33200103113 - 2¹⁴ = 33200086729 is a prime.

It is a super-2 number, since 2×33200103113² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 33200103091 and 33200103100.

It is not an unprimeable number, because it can be changed into a prime (33200103119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 283943 + ... + 383436.

It is an arithmetic number, because the mean of its divisors is an integer number (8300205060).

Almost surely, 2^33200103113 is an apocalyptic number.

It is an amenable number.

33200103113 is a deficient number, since it is larger than the sum of its proper divisors (717127).

33200103113 is an equidigital number, since it uses as much as digits as its factorization.

33200103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 717126.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 33200103113 its reverse (31130100233), we get a palindrome (64330203346).

The spelling of 33200103113 in words is "thirty-three billion, two hundred million, one hundred three thousand, one hundred thirteen".