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332013000003 = 3110671000001
BaseRepresentation
bin1001101010011011000…
…01000101010101000011
31011201222120000220222220
410311031201011111003
520414430312000003
6412305154502123
732662406636016
oct4651541052503
91151876026886
10332013000003
11118895756aa3
125441a594943
1325402270269
14120d8a6b37d
158982db7353
hex4d4d845543

332013000003 has 4 divisors (see below), whose sum is σ = 442684000008. Its totient is φ = 221342000000.

The previous prime is 332012999987. The next prime is 332013000043. The reversal of 332013000003 is 300000310233.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 332013000003 - 24 = 332012999987 is a prime.

It is a super-2 number, since 2×3320130000032 (a number of 24 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (332013000043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55335499998 + ... + 55335500003.

It is an arithmetic number, because the mean of its divisors is an integer number (110671000002).

Almost surely, 2332013000003 is an apocalyptic number.

332013000003 is a deficient number, since it is larger than the sum of its proper divisors (110671000005).

332013000003 is a wasteful number, since it uses less digits than its factorization.

332013000003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110671000004.

The product of its (nonzero) digits is 162, while the sum is 15.

Adding to 332013000003 its reverse (300000310233), we get a palindrome (632013310236).

The spelling of 332013000003 in words is "three hundred thirty-two billion, thirteen million, three", and thus it is an aban number.

Divisors: 1 3 110671000001 332013000003