Base | Representation |
---|---|
bin | 11110111011101101… |
… | …011100010111011011 |
3 | 10011201202001012020212 |
4 | 132323231130113123 |
5 | 1021010242220011 |
6 | 23131443441335 |
7 | 2254034352452 |
oct | 367355342733 |
9 | 104652035225 |
10 | 33214023131 |
11 | 130a44a51a3 |
12 | 652b38624b |
13 | 3194203733 |
14 | 1871243b99 |
15 | ce5d9708b |
hex | 7bbb5c5db |
33214023131 has 4 divisors (see below), whose sum is σ = 34285443264. Its totient is φ = 32142603000.
The previous prime is 33214023083. The next prime is 33214023179. The reversal of 33214023131 is 13132041233.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (33214023083) and next prime (33214023179).
It is a cyclic number.
It is not a de Polignac number, because 33214023131 - 226 = 33146914267 is a prime.
It is a super-3 number, since 3×332140231313 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 33214023097 and 33214023106.
It is not an unprimeable number, because it can be changed into a prime (33214022131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 535710020 + ... + 535710081.
It is an arithmetic number, because the mean of its divisors is an integer number (8571360816).
Almost surely, 233214023131 is an apocalyptic number.
33214023131 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
33214023131 is a deficient number, since it is larger than the sum of its proper divisors (1071420133).
33214023131 is a wasteful number, since it uses less digits than its factorization.
33214023131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1071420132.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 33214023131 its reverse (13132041233), we get a palindrome (46346064364).
The spelling of 33214023131 in words is "thirty-three billion, two hundred fourteen million, twenty-three thousand, one hundred thirty-one".
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