Base | Representation |
---|---|
bin | 1100011010001111… |
… | …1000011110001001 |
3 | 22121011102022210111 |
4 | 3012203320132021 |
5 | 23310302420423 |
6 | 1310321114321 |
7 | 145360353436 |
oct | 30643703611 |
9 | 8534368714 |
10 | 3331295113 |
11 | 145a47a363 |
12 | 78b7889a1 |
13 | 41121b953 |
14 | 238604b8d |
15 | 1476d560d |
hex | c68f8789 |
3331295113 has 8 divisors (see below), whose sum is σ = 3371486976. Its totient is φ = 3291254400.
The previous prime is 3331295101. The next prime is 3331295119. The reversal of 3331295113 is 3115921333.
3331295113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3331295113 - 217 = 3331164041 is a prime.
It is a super-2 number, since 2×33312951132 = 22195054259795365538, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3331295119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6873 + ... + 81913.
It is an arithmetic number, because the mean of its divisors is an integer number (421435872).
Almost surely, 23331295113 is an apocalyptic number.
It is an amenable number.
3331295113 is a deficient number, since it is larger than the sum of its proper divisors (40191863).
3331295113 is a wasteful number, since it uses less digits than its factorization.
3331295113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75575.
The product of its digits is 7290, while the sum is 31.
The square root of 3331295113 is about 57717.3727139412. The cubic root of 3331295113 is about 1493.4970504311.
The spelling of 3331295113 in words is "three billion, three hundred thirty-one million, two hundred ninety-five thousand, one hundred thirteen".
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