3341114433 has 16 divisors (see below), whose sum is σ = 4952511360. Its totient is φ = 2226189168.

The previous prime is 3341114423. The next prime is 3341114437. The reversal of 3341114433 is 3344111433.

It is not a de Polignac number, because 3341114433 - 2⁸ = 3341114177 is a prime.

It is a super-2 number, since 2×3341114433² = 22326091308801822978, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 3341114397 and 3341114406.

It is not an unprimeable number, because it can be changed into a prime (3341114437) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17716 + ... + 83642.

It is an arithmetic number, because the mean of its divisors is an integer number (309531960).

Almost surely, 2^3341114433 is an apocalyptic number.

It is an amenable number.

3341114433 is a deficient number, since it is larger than the sum of its proper divisors (1611396927).

3341114433 is a wasteful number, since it uses less digits than its factorization.

3341114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67813 (or 67807 counting only the distinct ones).

The product of its digits is 5184, while the sum is 27.

The square root of 3341114433 is about 57802.3739391385. The cubic root of 3341114433 is about 1494.9630208263.

Adding to 3341114433 its reverse (3344111433), we get a palindrome (6685225866).

The spelling of 3341114433 in words is "three billion, three hundred forty-one million, one hundred fourteen thousand, four hundred thirty-three".