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334144314251 = 1130376755841
BaseRepresentation
bin1001101110011001000…
…11011001101110001011
31011221111002110220111122
410313030203121232023
520433311421024001
6413300452145455
733066256544126
oct4671443315613
91157432426448
10334144314251
11119789832a30
125491430828b
13256819a3357
141225bb493bd
158a5a067b1b
hex4dcc8d9b8b

334144314251 has 4 divisors (see below), whose sum is σ = 364521070104. Its totient is φ = 303767558400.

The previous prime is 334144314191. The next prime is 334144314263. The reversal of 334144314251 is 152413441433.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 334144314251 - 210 = 334144313227 is a prime.

It is a super-2 number, since 2×3341443142512 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (334144314271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15188377910 + ... + 15188377931.

It is an arithmetic number, because the mean of its divisors is an integer number (91130267526).

Almost surely, 2334144314251 is an apocalyptic number.

334144314251 is a deficient number, since it is larger than the sum of its proper divisors (30376755853).

334144314251 is a wasteful number, since it uses less digits than its factorization.

334144314251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30376755852.

The product of its digits is 69120, while the sum is 35.

Adding to 334144314251 its reverse (152413441433), we get a palindrome (486557755684).

The spelling of 334144314251 in words is "three hundred thirty-four billion, one hundred forty-four million, three hundred fourteen thousand, two hundred fifty-one".

Divisors: 1 11 30376755841 334144314251