3342414433 has 4 divisors (see below), whose sum is σ = 3366460720. Its totient is φ = 3318368148.

The previous prime is 3342414407. The next prime is 3342414437. The reversal of 3342414433 is 3344142433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3344142433 = 36017 ⋅92849.

It is a cyclic number.

It is not a de Polignac number, because 3342414433 - 2¹³ = 3342406241 is a prime.

It is a super-2 number, since 2×3342414433² = 22343468483853422978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3342414395 and 3342414404.

It is not an unprimeable number, because it can be changed into a prime (3342414437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12022935 + ... + 12023212.

It is an arithmetic number, because the mean of its divisors is an integer number (841615180).

Almost surely, 2^3342414433 is an apocalyptic number.

It is an amenable number.

3342414433 is a deficient number, since it is larger than the sum of its proper divisors (24046287).

3342414433 is a wasteful number, since it uses less digits than its factorization.

3342414433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24046286.

The product of its digits is 41472, while the sum is 31.

The square root of 3342414433 is about 57813.6180583779. The cubic root of 3342414433 is about 1495.1568882679.

Adding to 3342414433 its reverse (3344142433), we get a palindrome (6686556866).

Subtracting 3342414433 from its reverse (3344142433), we obtain a cube (1728000 = 120³).

The spelling of 3342414433 in words is "three billion, three hundred forty-two million, four hundred fourteen thousand, four hundred thirty-three".