3343116113433 has 12 divisors (see below), whose sum is σ = 4841109093028. Its totient is φ = 2223130108320.

The previous prime is 3343116113419. The next prime is 3343116113501.

3343116113433 is a `hidden beast` number, since 3 + 3 + 4 + 3 + 1 + 1 + 611 + 3 + 4 + 33 = 666.

3343116113433 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in 2 ways, for example, as 2232385609689 + 1110730503744 = 1494117^2 + 1053912^2 .

It is not a de Polignac number, because 3343116113433 - 2⁸ = 3343116113177 is a prime.

It is a super-2 number, since 2×3343116113433² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3343116113033) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 467826838 + ... + 467833983.

Almost surely, 2^{3343116113433} is an apocalyptic number.

It is an amenable number.

3343116113433 is a deficient number, since it is larger than the sum of its proper divisors (1497992979595).

3343116113433 is a wasteful number, since it uses less digits than its factorization.

3343116113433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 935661224 (or 935661221 counting only the distinct ones).

The product of its digits is 69984, while the sum is 36.

The spelling of 3343116113433 in words is "three trillion, three hundred forty-three billion, one hundred sixteen million, one hundred thirteen thousand, four hundred thirty-three".