3343311121 has 4 divisors (see below), whose sum is σ = 3343504752. Its totient is φ = 3343117492.

The previous prime is 3343311107. The next prime is 3343311133. The reversal of 3343311121 is 1211133433.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1211133433 = 509 ⋅2379437.

It is a cyclic number.

It is not a de Polignac number, because 3343311121 - 2⁵ = 3343311089 is a prime.

It is a super-2 number, since 2×3343311121² = 22355458503604553282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3343311092 and 3343311101.

It is not an unprimeable number, because it can be changed into a prime (3343311151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68071 + ... + 106396.

It is an arithmetic number, because the mean of its divisors is an integer number (835876188).

Almost surely, 2^3343311121 is an apocalyptic number.

It is an amenable number.

3343311121 is a deficient number, since it is larger than the sum of its proper divisors (193631).

3343311121 is a wasteful number, since it uses less digits than its factorization.

3343311121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 193630.

The product of its digits is 648, while the sum is 22.

The square root of 3343311121 is about 57821.3725278119. The cubic root of 3343311121 is about 1495.2905809814.

Adding to 3343311121 its reverse (1211133433), we get a palindrome (4554444554).

The spelling of 3343311121 in words is "three billion, three hundred forty-three million, three hundred eleven thousand, one hundred twenty-one".