Base | Representation |
---|---|
bin | 100110000001011001100111… |
… | …1110100110011100000110001 |
3 | 1121212011112102101220200002011 |
4 | 1030002303033310303200301 |
5 | 322314012303013143441 |
6 | 3143145241433122521 |
7 | 130305532046055166 |
oct | 11402631764634061 |
9 | 1555145371820064 |
10 | 334444000131121 |
11 | 976229a4156271 |
12 | 316155a2b59441 |
13 | 1147cc1a99966a |
14 | 5c83266c3c06d |
15 | 289e9c8c72581 |
hex | 1302ccfd33831 |
334444000131121 has 4 divisors (see below), whose sum is σ = 334449831920500. Its totient is φ = 334438168341744.
The previous prime is 334444000131097. The next prime is 334444000131133. The reversal of 334444000131121 is 121131000444433.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 271918780801600 + 62525219329521 = 16489960^2 + 7907289^2 .
It is a cyclic number.
It is not a de Polignac number, because 334444000131121 - 25 = 334444000131089 is a prime.
It is a super-2 number, since 2×3344440001311212 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (334444000131191) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2915808666 + ... + 2915923363.
It is an arithmetic number, because the mean of its divisors is an integer number (83612457980125).
Almost surely, 2334444000131121 is an apocalyptic number.
It is an amenable number.
334444000131121 is a deficient number, since it is larger than the sum of its proper divisors (5831789379).
334444000131121 is an equidigital number, since it uses as much as digits as its factorization.
334444000131121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5831789378.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 334444000131121 its reverse (121131000444433), we get a palindrome (455575000575554).
The spelling of 334444000131121 in words is "three hundred thirty-four trillion, four hundred forty-four billion, one hundred thirty-one thousand, one hundred twenty-one".
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