Base | Representation |
---|---|
bin | 10011111101000… |
… | …111110101000001 |
3 | 212022222002110220 |
4 | 103331013311001 |
5 | 1141201234303 |
6 | 53115413253 |
7 | 11203445001 |
oct | 2375076501 |
9 | 768862426 |
10 | 334789953 |
11 | 161a86713 |
12 | 94154229 |
13 | 5448c084 |
14 | 3266c001 |
15 | 1e5d2053 |
hex | 13f47d41 |
334789953 has 4 divisors (see below), whose sum is σ = 446386608. Its totient is φ = 223193300.
The previous prime is 334789951. The next prime is 334789963. The reversal of 334789953 is 359987433.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 334789953 - 21 = 334789951 is a prime.
It is a super-2 number, since 2×3347899532 = 224168625259484418, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 334789896 and 334789905.
It is not an unprimeable number, because it can be changed into a prime (334789951) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55798323 + ... + 55798328.
It is an arithmetic number, because the mean of its divisors is an integer number (111596652).
Almost surely, 2334789953 is an apocalyptic number.
It is an amenable number.
334789953 is a deficient number, since it is larger than the sum of its proper divisors (111596655).
334789953 is a wasteful number, since it uses less digits than its factorization.
334789953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111596654.
The product of its digits is 2449440, while the sum is 51.
The square root of 334789953 is about 18297.2662712220. The cubic root of 334789953 is about 694.3697704471.
The spelling of 334789953 in words is "three hundred thirty-four million, seven hundred eighty-nine thousand, nine hundred fifty-three".
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