Base | Representation |
---|---|
bin | 11111001100100100… |
… | …010101111111100001 |
3 | 10012110110020022022221 |
4 | 133030210111333201 |
5 | 1022100143203101 |
6 | 23215505431041 |
7 | 2264040346660 |
oct | 371444257741 |
9 | 105413208287 |
10 | 33496850401 |
11 | 1322a10a543 |
12 | 65aa03b481 |
13 | 320a99ac51 |
14 | 189aa26dd7 |
15 | d10b12aa1 |
hex | 7cc915fe1 |
33496850401 has 4 divisors (see below), whose sum is σ = 38282114752. Its totient is φ = 28711586052.
The previous prime is 33496850381. The next prime is 33496850417. The reversal of 33496850401 is 10405869433.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 33496850401 - 221 = 33494753249 is a prime.
It is a super-2 number, since 2×334968504012 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (33496856401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2392632165 + ... + 2392632178.
It is an arithmetic number, because the mean of its divisors is an integer number (9570528688).
Almost surely, 233496850401 is an apocalyptic number.
It is an amenable number.
33496850401 is a deficient number, since it is larger than the sum of its proper divisors (4785264351).
33496850401 is an equidigital number, since it uses as much as digits as its factorization.
33496850401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4785264350.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 33496850401 in words is "thirty-three billion, four hundred ninety-six million, eight hundred fifty thousand, four hundred one".
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