Base | Representation |
---|---|
bin | 1001101111111111100… |
… | …11001111010101001011 |
3 | 1012000201000022202022211 |
4 | 10313333303033111023 |
5 | 20442042022312021 |
6 | 413522044325551 |
7 | 33126466620613 |
oct | 4677763172513 |
9 | 1160630282284 |
10 | 335004104011 |
11 | 11a0900a0785 |
12 | 54b142438b7 |
13 | 2578ab5b5a5 |
14 | 122dddd9a43 |
15 | 8aaa7a03e1 |
hex | 4dffccf54b |
335004104011 has 4 divisors (see below), whose sum is σ = 335014228000. Its totient is φ = 334993980024.
The previous prime is 335004103981. The next prime is 335004104027. The reversal of 335004104011 is 110401400533.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 335004104011 - 25 = 335004103979 is a prime.
It is a super-2 number, since 2×3350041040112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (335004101011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5012196 + ... + 5078593.
It is an arithmetic number, because the mean of its divisors is an integer number (83753557000).
Almost surely, 2335004104011 is an apocalyptic number.
335004104011 is a deficient number, since it is larger than the sum of its proper divisors (10123989).
335004104011 is a wasteful number, since it uses less digits than its factorization.
335004104011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10123988.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 335004104011 its reverse (110401400533), we get a palindrome (445405504544).
The spelling of 335004104011 in words is "three hundred thirty-five billion, four million, one hundred four thousand, eleven".
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