Base | Representation |
---|---|
bin | 110000110001111011111… |
… | …001010001111010110011 |
3 | 102212110111022110111022120 |
4 | 300301323321101322303 |
5 | 414410202143312201 |
6 | 11043542522405323 |
7 | 464120323152453 |
oct | 60617371217263 |
9 | 12773438414276 |
10 | 3352153104051 |
11 | 1082705044a64 |
12 | 461805360843 |
13 | 1b41504c059b |
14 | b83606b9d63 |
15 | 5c2e57ee536 |
hex | 30c7be51eb3 |
3352153104051 has 8 divisors (see below), whose sum is σ = 4469546026944. Its totient is φ = 2234764458600.
The previous prime is 3352153104049. The next prime is 3352153104077. The reversal of 3352153104051 is 1504013512533.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3352153104051 - 21 = 3352153104049 is a prime.
It is a super-2 number, since 2×33521531040512 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (3352153124051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2107476 + ... + 3338526.
It is an arithmetic number, because the mean of its divisors is an integer number (558693253368).
Almost surely, 23352153104051 is an apocalyptic number.
3352153104051 is a deficient number, since it is larger than the sum of its proper divisors (1117392922893).
3352153104051 is a wasteful number, since it uses less digits than its factorization.
3352153104051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2138721.
The product of its (nonzero) digits is 27000, while the sum is 33.
Adding to 3352153104051 its reverse (1504013512533), we get a palindrome (4856166616584).
The spelling of 3352153104051 in words is "three trillion, three hundred fifty-two billion, one hundred fifty-three million, one hundred four thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •