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3380171681417 = 8137341539229
BaseRepresentation
bin110001001100000001111…
…011101010111010001001
3102222010210222100200211012
4301030001323222322021
5420340042422301132
611104455054013305
7466131543142106
oct61140173527211
912863728320735
103380171681417
11109358287a923
124671247a7235
131b699721404b
14b985b903aad
155cdd54d50b2
hex31301eeae89

3380171681417 has 4 divisors (see below), whose sum is σ = 3380213302020. Its totient is φ = 3380130060816.

The previous prime is 3380171681407. The next prime is 3380171681429. The reversal of 3380171681417 is 7141861710833.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3129021361216 + 251150320201 = 1768904^2 + 501149^2 .

It is a cyclic number.

It is not a de Polignac number, because 3380171681417 - 26 = 3380171681353 is a prime.

It is a super-2 number, since 2×33801716814172 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3380171681407) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20688242 + ... + 20850987.

It is an arithmetic number, because the mean of its divisors is an integer number (845053325505).

Almost surely, 23380171681417 is an apocalyptic number.

It is an amenable number.

3380171681417 is a deficient number, since it is larger than the sum of its proper divisors (41620603).

3380171681417 is an equidigital number, since it uses as much as digits as its factorization.

3380171681417 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41620602.

The product of its (nonzero) digits is 677376, while the sum is 50.

The spelling of 3380171681417 in words is "three trillion, three hundred eighty billion, one hundred seventy-one million, six hundred eighty-one thousand, four hundred seventeen".

Divisors: 1 81373 41539229 3380171681417