Base | Representation |
---|---|
bin | 110001011000000110010… |
… | …110101001010010011001 |
3 | 110000101021010011021100012 |
4 | 301120012112221102121 |
5 | 421043112433412132 |
6 | 11114441024051305 |
7 | 500100641416223 |
oct | 61300626512231 |
9 | 13011233137305 |
10 | 3393130763417 |
11 | 1099022947a4a |
12 | 469740763b35 |
13 | 1b7c80c8a3c5 |
14 | ba32aa5b413 |
15 | 5d3e30530b2 |
hex | 316065a9499 |
3393130763417 has 4 divisors (see below), whose sum is σ = 3393176714676. Its totient is φ = 3393084812160.
The previous prime is 3393130763389. The next prime is 3393130763419. The reversal of 3393130763417 is 7143670313933.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3138013845136 + 255116918281 = 1771444^2 + 505091^2 .
It is a cyclic number.
It is not a de Polignac number, because 3393130763417 - 230 = 3392057021593 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3393130763419) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22864688 + ... + 23012609.
It is an arithmetic number, because the mean of its divisors is an integer number (848294178669).
Almost surely, 23393130763417 is an apocalyptic number.
It is an amenable number.
3393130763417 is a deficient number, since it is larger than the sum of its proper divisors (45951259).
3393130763417 is an equidigital number, since it uses as much as digits as its factorization.
3393130763417 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45951258.
The product of its (nonzero) digits is 2571912, while the sum is 50.
The spelling of 3393130763417 in words is "three trillion, three hundred ninety-three billion, one hundred thirty million, seven hundred sixty-three thousand, four hundred seventeen".
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