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340013113403 = 719472897237
BaseRepresentation
bin1001111001010100101…
…11000110000000111011
31012111122002122210110012
410330222113012000323
521032321324112103
6420111101012135
733364561530545
oct4745227060073
91174562583405
10340013113403
111212205a1667
1255a9185404b
13260a8822b82
1412657364695
158ca03d62d8
hex4f2a5c603b

340013113403 has 4 divisors (see below), whose sum is σ = 340486011360. Its totient is φ = 339540215448.

The previous prime is 340013113397. The next prime is 340013113499. The reversal of 340013113403 is 304311310043.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 340013113403 - 214 = 340013097019 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (340013113003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236447900 + ... + 236449337.

It is an arithmetic number, because the mean of its divisors is an integer number (85121502840).

Almost surely, 2340013113403 is an apocalyptic number.

340013113403 is a deficient number, since it is larger than the sum of its proper divisors (472897957).

340013113403 is an equidigital number, since it uses as much as digits as its factorization.

340013113403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 472897956.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 340013113403 its reverse (304311310043), we get a palindrome (644324423446).

The spelling of 340013113403 in words is "three hundred forty billion, thirteen million, one hundred thirteen thousand, four hundred three".

Divisors: 1 719 472897237 340013113403