Base | Representation |
---|---|
bin | 1001111001100010110… |
… | …00110010111110001001 |
3 | 1012111221022111001201220 |
4 | 10330301120302332021 |
5 | 21033042014001301 |
6 | 420130511432253 |
7 | 33400522541046 |
oct | 4746130627611 |
9 | 1174838431656 |
10 | 340131000201 |
11 | 12128109a773 |
12 | 55b05225689 |
13 | 260c7089c85 |
14 | 12668c901cd |
15 | 8caa920936 |
hex | 4f31632f89 |
340131000201 has 4 divisors (see below), whose sum is σ = 453508000272. Its totient is φ = 226754000132.
The previous prime is 340131000193. The next prime is 340131000217. The reversal of 340131000201 is 102000131043.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 340131000201 - 23 = 340131000193 is a prime.
It is not an unprimeable number, because it can be changed into a prime (340131000241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56688500031 + ... + 56688500036.
It is an arithmetic number, because the mean of its divisors is an integer number (113377000068).
Almost surely, 2340131000201 is an apocalyptic number.
It is an amenable number.
340131000201 is a deficient number, since it is larger than the sum of its proper divisors (113377000071).
340131000201 is a wasteful number, since it uses less digits than its factorization.
340131000201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113377000070.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 340131000201 its reverse (102000131043), we get a palindrome (442131131244).
The spelling of 340131000201 in words is "three hundred forty billion, one hundred thirty-one million, two hundred one", and thus it is an aban number.
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