Base | Representation |
---|---|
bin | 1001111001100100011… |
… | …11010110011001111001 |
3 | 1012111222022101121220022 |
4 | 10330302033112121321 |
5 | 21033104144113423 |
6 | 420132142140225 |
7 | 33401055232502 |
oct | 4746217263171 |
9 | 1174868347808 |
10 | 340145301113 |
11 | 121289178202 |
12 | 55b09b81675 |
13 | 260ca026357 |
14 | 1266ab33ba9 |
15 | 8cabce7dc8 |
hex | 4f323d6679 |
340145301113 has 4 divisors (see below), whose sum is σ = 345222096720. Its totient is φ = 335068505508.
The previous prime is 340145301107. The next prime is 340145301143. The reversal of 340145301113 is 311103541043.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311103541043 = 109 ⋅2854160927.
It is a cyclic number.
It is not a de Polignac number, because 340145301113 - 26 = 340145301049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (340145301143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2538397703 + ... + 2538397836.
It is an arithmetic number, because the mean of its divisors is an integer number (86305524180).
Almost surely, 2340145301113 is an apocalyptic number.
It is an amenable number.
340145301113 is a deficient number, since it is larger than the sum of its proper divisors (5076795607).
340145301113 is an equidigital number, since it uses as much as digits as its factorization.
340145301113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5076795606.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 340145301113 its reverse (311103541043), we get a palindrome (651248842156).
The spelling of 340145301113 in words is "three hundred forty billion, one hundred forty-five million, three hundred one thousand, one hundred thirteen".
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