3403042541131 has 4 divisors (see below), whose sum is σ = 3413914881832. Its totient is φ = 3392170200432.

The previous prime is 3403042541089. The next prime is 3403042541141. The reversal of 3403042541131 is 1311452403043.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3403042541131 - 2³³ = 3394452606539 is a prime.

It is a super-2 number, since 2×3403042541131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3403042541093 and 3403042541102.

It is not an unprimeable number, because it can be changed into a prime (3403042541141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5436169881 + ... + 5436170506.

It is an arithmetic number, because the mean of its divisors is an integer number (853478720458).

Almost surely, 2^{3403042541131} is an apocalyptic number.

3403042541131 is a deficient number, since it is larger than the sum of its proper divisors (10872340701).

3403042541131 is a wasteful number, since it uses less digits than its factorization.

3403042541131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10872340700.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 3403042541131 its reverse (1311452403043), we get a palindrome (4714494944174).

The spelling of 3403042541131 in words is "three trillion, four hundred three billion, forty-two million, five hundred forty-one thousand, one hundred thirty-one".