Base | Representation |
---|---|
bin | 11111101100100101… |
… | …110111101001101011 |
3 | 10020211220012111110222 |
4 | 133230211313221223 |
5 | 1024200213340243 |
6 | 23345101200255 |
7 | 2313253154336 |
oct | 375445675153 |
9 | 106756174428 |
10 | 34034121323 |
11 | 134854130a4 |
12 | 6719b6008b |
13 | 32950a2637 |
14 | 190c12161d |
15 | d42d8e168 |
hex | 7ec977a6b |
34034121323 has 4 divisors (see below), whose sum is σ = 34048441800. Its totient is φ = 34019800848.
The previous prime is 34034121301. The next prime is 34034121371. The reversal of 34034121323 is 32312143043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 34034121323 - 28 = 34034121067 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34034121292 and 34034121301.
It is not an unprimeable number, because it can be changed into a prime (34034124323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7156673 + ... + 7161426.
It is an arithmetic number, because the mean of its divisors is an integer number (8512110450).
Almost surely, 234034121323 is an apocalyptic number.
34034121323 is a deficient number, since it is larger than the sum of its proper divisors (14320477).
34034121323 is a wasteful number, since it uses less digits than its factorization.
34034121323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14320476.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 34034121323 its reverse (32312143043), we get a palindrome (66346264366).
The spelling of 34034121323 in words is "thirty-four billion, thirty-four million, one hundred twenty-one thousand, three hundred twenty-three".
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