340401114113033 has 4 divisors (see below), whose sum is σ = 343524060114180. Its totient is φ = 337278168111888.

The previous prime is 340401114112993. The next prime is 340401114113087. The reversal of 340401114113033 is 330311411104043.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 206054770833664 + 134346343279369 = 14354608^2 + 11590787^2 .

It is a cyclic number.

It is not a de Polignac number, because 340401114113033 - 2³⁸ = 340126236206089 is a prime.

It is a super-2 number, since 2×340401114113033² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 340401114112987 and 340401114113005.

It is not an unprimeable number, because it can be changed into a prime (340401114113233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1561473000410 + ... + 1561473000627.

It is an arithmetic number, because the mean of its divisors is an integer number (85881015028545).

Almost surely, 2^{340401114113033} is an apocalyptic number.

It is an amenable number.

340401114113033 is a deficient number, since it is larger than the sum of its proper divisors (3122946001147).

340401114113033 is a wasteful number, since it uses less digits than its factorization.

340401114113033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3122946001146.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 340401114113033 its reverse (330311411104043), we get a palindrome (670712525217076).

The spelling of 340401114113033 in words is "three hundred forty trillion, four hundred one billion, one hundred fourteen million, one hundred thirteen thousand, thirty-three".