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340411311143203 = 658151726380663
BaseRepresentation
bin100110101100110100010111…
…1010001110011100100100011
31122122022000002120100120122011
41031121220233101303210203
5324104244331123040303
63203554444125453351
7131462622425550526
oct11531505721634443
91578260076316564
10340411311143203
11995136986aa223
1232219bab411257
13117c3858835051
14600bdd1418bbd
152954d2cec416d
hex1359a2f473923

340411311143203 has 4 divisors (see below), whose sum is σ = 340463037530448. Its totient is φ = 340359584755960.

The previous prime is 340411311143191. The next prime is 340411311143219. The reversal of 340411311143203 is 302341113114043.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-340411311143203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (340411311143003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25863183751 + ... + 25863196912.

It is an arithmetic number, because the mean of its divisors is an integer number (85115759382612).

Almost surely, 2340411311143203 is an apocalyptic number.

340411311143203 is a deficient number, since it is larger than the sum of its proper divisors (51726387245).

340411311143203 is an equidigital number, since it uses as much as digits as its factorization.

340411311143203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51726387244.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 340411311143203 its reverse (302341113114043), we get a palindrome (642752424257246).

The spelling of 340411311143203 in words is "three hundred forty trillion, four hundred eleven billion, three hundred eleven million, one hundred forty-three thousand, two hundred three".

Divisors: 1 6581 51726380663 340411311143203