Base | Representation |
---|---|
bin | 100110101100110100010111… |
… | …1010001110011100100100011 |
3 | 1122122022000002120100120122011 |
4 | 1031121220233101303210203 |
5 | 324104244331123040303 |
6 | 3203554444125453351 |
7 | 131462622425550526 |
oct | 11531505721634443 |
9 | 1578260076316564 |
10 | 340411311143203 |
11 | 995136986aa223 |
12 | 32219bab411257 |
13 | 117c3858835051 |
14 | 600bdd1418bbd |
15 | 2954d2cec416d |
hex | 1359a2f473923 |
340411311143203 has 4 divisors (see below), whose sum is σ = 340463037530448. Its totient is φ = 340359584755960.
The previous prime is 340411311143191. The next prime is 340411311143219. The reversal of 340411311143203 is 302341113114043.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-340411311143203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (340411311143003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25863183751 + ... + 25863196912.
It is an arithmetic number, because the mean of its divisors is an integer number (85115759382612).
Almost surely, 2340411311143203 is an apocalyptic number.
340411311143203 is a deficient number, since it is larger than the sum of its proper divisors (51726387245).
340411311143203 is an equidigital number, since it uses as much as digits as its factorization.
340411311143203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51726387244.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 340411311143203 its reverse (302341113114043), we get a palindrome (642752424257246).
The spelling of 340411311143203 in words is "three hundred forty trillion, four hundred eleven billion, three hundred eleven million, one hundred forty-three thousand, two hundred three".
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