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341015113 = 794316647
BaseRepresentation
bin10100010100110…
…111101001001001
3212202200100210101
4110110313221021
51144244440423
653501045401
711310403105
oct2424675111
9782610711
10341015113
1116554877a
1296256861
135585b6ba
143340c905
151ee117ad
hex14537a49

341015113 has 4 divisors (see below), whose sum is σ = 345331840. Its totient is φ = 336698388.

The previous prime is 341015083. The next prime is 341015123. The reversal of 341015113 is 311510143.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 341015113 - 221 = 338917961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (341015123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2158245 + ... + 2158402.

It is an arithmetic number, because the mean of its divisors is an integer number (86332960).

Almost surely, 2341015113 is an apocalyptic number.

It is an amenable number.

341015113 is a deficient number, since it is larger than the sum of its proper divisors (4316727).

341015113 is an equidigital number, since it uses as much as digits as its factorization.

341015113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4316726.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 341015113 is about 18466.5945155029. The cubic root of 341015113 is about 698.6471237418.

Adding to 341015113 its reverse (311510143), we get a palindrome (652525256).

The spelling of 341015113 in words is "three hundred forty-one million, fifteen thousand, one hundred thirteen".

Divisors: 1 79 4316647 341015113