3410412001131 has 4 divisors (see below), whose sum is σ = 4547216001512. Its totient is φ = 2273608000752.

The previous prime is 3410412001123. The next prime is 3410412001141. The reversal of 3410412001131 is 1311002140143.

3410412001131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 3410412001131 - 2³ = 3410412001123 is a prime.

It is a super-2 number, since 2×3410412001131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3410412001098 and 3410412001107.

It is not an unprimeable number, because it can be changed into a prime (3410412001141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 568402000186 + ... + 568402000191.

It is an arithmetic number, because the mean of its divisors is an integer number (1136804000378).

Almost surely, 2^{3410412001131} is an apocalyptic number.

3410412001131 is a deficient number, since it is larger than the sum of its proper divisors (1136804000381).

3410412001131 is a wasteful number, since it uses less digits than its factorization.

3410412001131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1136804000380.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 3410412001131 its reverse (1311002140143), we get a palindrome (4721414141274).

The spelling of 3410412001131 in words is "three trillion, four hundred ten billion, four hundred twelve million, one thousand, one hundred thirty-one".