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341114201435 = 573198900409
BaseRepresentation
bin1001111011010111111…
…11011010010101011011
31012121110211112212021102
410331223333122111123
521042100213421220
6420412233102015
733434061605000
oct4755377322533
91177424485242
10341114201435
1112173608a377
125613a55790b
1326222994b57
141271d6a78a7
158d16dd4775
hex4f6bfda55b

341114201435 has 16 divisors (see below), whose sum is σ = 477360984000. Its totient is φ = 233906879808.

The previous prime is 341114201423. The next prime is 341114201453. The reversal of 341114201435 is 534102411143.

It is not a de Polignac number, because 341114201435 - 232 = 336819234139 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 341114201398 and 341114201407.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 99448490 + ... + 99451919.

It is an arithmetic number, because the mean of its divisors is an integer number (29835061500).

Almost surely, 2341114201435 is an apocalyptic number.

341114201435 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

341114201435 is a deficient number, since it is larger than the sum of its proper divisors (136246782565).

341114201435 is an equidigital number, since it uses as much as digits as its factorization.

341114201435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 198900435 (or 198900421 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 341114201435 its reverse (534102411143), we get a palindrome (875216612578).

The spelling of 341114201435 in words is "three hundred forty-one billion, one hundred fourteen million, two hundred one thousand, four hundred thirty-five".

Divisors: 1 5 7 35 49 245 343 1715 198900409 994502045 1392302863 6961514315 9746120041 48730600205 68222840287 341114201435