Base | Representation |
---|---|
bin | 110001101010001100000… |
… | …001100100001001001011 |
3 | 110002020101200222222211221 |
4 | 301222030001210021023 |
5 | 421402402113102301 |
6 | 11131412203302511 |
7 | 501356152023466 |
oct | 61521401441113 |
9 | 13066350888757 |
10 | 3412553253451 |
11 | 10a628a38a201 |
12 | 47146121aa37 |
13 | 1b9a57b12064 |
14 | bb2503722dd |
15 | 5db7d244da1 |
hex | 31a8c06424b |
3412553253451 has 4 divisors (see below), whose sum is σ = 3530227503600. Its totient is φ = 3294879003304.
The previous prime is 3412553253443. The next prime is 3412553253463. The reversal of 3412553253451 is 1543523552143.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3412553253451 - 23 = 3412553253443 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3412553253398 and 3412553253407.
It is not an unprimeable number, because it can be changed into a prime (3412553253491) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58837125031 + ... + 58837125088.
It is an arithmetic number, because the mean of its divisors is an integer number (882556875900).
Almost surely, 23412553253451 is an apocalyptic number.
3412553253451 is a deficient number, since it is larger than the sum of its proper divisors (117674250149).
3412553253451 is a wasteful number, since it uses less digits than its factorization.
3412553253451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117674250148.
The product of its digits is 1080000, while the sum is 43.
The spelling of 3412553253451 in words is "three trillion, four hundred twelve billion, five hundred fifty-three million, two hundred fifty-three thousand, four hundred fifty-one".
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