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3413244332011 = 5216551332691
BaseRepresentation
bin110001101010110101001…
…101110100011111101011
3110002022011212101102102011
4301222311031310133223
5421410311022111021
611132004531420351
7501412243060003
oct61526515643753
913068155342364
103413244332011
1110a6604495808
124716147546b7
131b9b38049797
14bb2b8067003
155dbbdc53de1
hex31ab53747eb

3413244332011 has 4 divisors (see below), whose sum is σ = 3419795665224. Its totient is φ = 3406692998800.

The previous prime is 3413244331999. The next prime is 3413244332027. The reversal of 3413244332011 is 1102334423143.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3413244332011 - 27 = 3413244331883 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3413244332411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3275665825 + ... + 3275666866.

It is an arithmetic number, because the mean of its divisors is an integer number (854948916306).

Almost surely, 23413244332011 is an apocalyptic number.

3413244332011 is a deficient number, since it is larger than the sum of its proper divisors (6551333213).

3413244332011 is an equidigital number, since it uses as much as digits as its factorization.

3413244332011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6551333212.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 3413244332011 its reverse (1102334423143), we get a palindrome (4515578755154).

The spelling of 3413244332011 in words is "three trillion, four hundred thirteen billion, two hundred forty-four million, three hundred thirty-two thousand, eleven".

Divisors: 1 521 6551332691 3413244332011