Base | Representation |
---|---|
bin | 110001101010111001111… |
… | …010000101100010001001 |
3 | 110002022101100111110100002 |
4 | 301222321322011202021 |
5 | 421410441144420001 |
6 | 11132020422452345 |
7 | 501414220112642 |
oct | 61527172054211 |
9 | 13068340443302 |
10 | 3413323045001 |
11 | 10a6644967a71 |
12 | 471636b940b5 |
13 | 1b9b4b44910c |
14 | bb2c46b66c9 |
15 | 5dbc5b0146b |
hex | 31ab9e85889 |
3413323045001 has 4 divisors (see below), whose sum is σ = 3414183478272. Its totient is φ = 3412462611732.
The previous prime is 3413323044997. The next prime is 3413323045037. The reversal of 3413323045001 is 1005403233143.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3413323045001 - 22 = 3413323044997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3413323045051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 430210685 + ... + 430218618.
It is an arithmetic number, because the mean of its divisors is an integer number (853545869568).
Almost surely, 23413323045001 is an apocalyptic number.
It is an amenable number.
3413323045001 is a deficient number, since it is larger than the sum of its proper divisors (860433271).
3413323045001 is an equidigital number, since it uses as much as digits as its factorization.
3413323045001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 860433270.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 3413323045001 its reverse (1005403233143), we get a palindrome (4418726278144).
The spelling of 3413323045001 in words is "three trillion, four hundred thirteen billion, three hundred twenty-three million, forty-five thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •