Base | Representation |
---|---|
bin | 11111110010100100… |
… | …110010011101110011 |
3 | 10021002220002022211111 |
4 | 133302210302131303 |
5 | 1024401413014420 |
6 | 23403044454151 |
7 | 2315612321212 |
oct | 376244623563 |
9 | 107086068744 |
10 | 34134501235 |
11 | 13527043aaa |
12 | 67476aa357 |
13 | 32acb1a033 |
14 | 191b5b1079 |
15 | d4babb45a |
hex | 7f2932773 |
34134501235 has 4 divisors (see below), whose sum is σ = 40961401488. Its totient is φ = 27307600984.
The previous prime is 34134501221. The next prime is 34134501239. The reversal of 34134501235 is 53210543143.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53210543143 = 3221 ⋅16519883.
It is a cyclic number.
It is not a de Polignac number, because 34134501235 - 29 = 34134500723 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 34134501197 and 34134501206.
It is not an unprimeable number, because it can be changed into a prime (34134501239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3413450119 + ... + 3413450128.
It is an arithmetic number, because the mean of its divisors is an integer number (10240350372).
Almost surely, 234134501235 is an apocalyptic number.
34134501235 is a deficient number, since it is larger than the sum of its proper divisors (6826900253).
34134501235 is an equidigital number, since it uses as much as digits as its factorization.
34134501235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6826900252.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 34134501235 in words is "thirty-four billion, one hundred thirty-four million, five hundred one thousand, two hundred thirty-five".
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