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3414113 = 5216553
BaseRepresentation
bin1101000001100001100001
320102110021122
431001201201
51333222423
6201102025
741006453
oct15014141
96373248
103414113
111a2208a
121187915
13926cb1
1464c2d3
154768c8
hex341861

3414113 has 4 divisors (see below), whose sum is σ = 3421188. Its totient is φ = 3407040.

The previous prime is 3414107. The next prime is 3414121. The reversal of 3414113 is 3114143.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1067089 + 2347024 = 1033^2 + 1532^2 .

It is a cyclic number.

It is not a de Polignac number, because 3414113 - 28 = 3413857 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3414091 and 3414100.

It is not an unprimeable number, because it can be changed into a prime (3414163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2756 + ... + 3797.

It is an arithmetic number, because the mean of its divisors is an integer number (855297).

Almost surely, 23414113 is an apocalyptic number.

It is an amenable number.

3414113 is a deficient number, since it is larger than the sum of its proper divisors (7075).

3414113 is an equidigital number, since it uses as much as digits as its factorization.

3414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7074.

The product of its digits is 144, while the sum is 17.

The square root of 3414113 is about 1847.7318528401. The cubic root of 3414113 is about 150.5772277236.

Adding to 3414113 its reverse (3114143), we get a palindrome (6528256).

The spelling of 3414113 in words is "three million, four hundred fourteen thousand, one hundred thirteen".

Divisors: 1 521 6553 3414113