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3414330542051 = 111323876437357
BaseRepresentation
bin110001101011110101111…
…101011000011111100011
3110002101222120021121110122
4301223311331120133203
5421420022104321201
611132304412550455
7501451202520062
oct61536575303743
913071876247418
103414330542051
1110a7011641460
1247187848242b
131b9c7c0ac810
14bb37c4161d9
155dc342b3e1b
hex31af5f587e3

3414330542051 has 8 divisors (see below), whose sum is σ = 4011241476144. Its totient is φ = 2865172482720.

The previous prime is 3414330542047. The next prime is 3414330542087. The reversal of 3414330542051 is 1502450334143.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3414330542051 - 22 = 3414330542047 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3414330542011) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11938218536 + ... + 11938218821.

It is an arithmetic number, because the mean of its divisors is an integer number (501405184518).

Almost surely, 23414330542051 is an apocalyptic number.

3414330542051 is a deficient number, since it is larger than the sum of its proper divisors (596910934093).

3414330542051 is a wasteful number, since it uses less digits than its factorization.

3414330542051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23876437381.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 3414330542051 its reverse (1502450334143), we get a palindrome (4916780876194).

The spelling of 3414330542051 in words is "three trillion, four hundred fourteen billion, three hundred thirty million, five hundred forty-two thousand, fifty-one".

Divisors: 1 11 13 143 23876437357 262640810927 310393685641 3414330542051