Base | Representation |
---|---|
bin | 11111110110100100… |
… | …000100000110101011 |
3 | 10021021120000011101210 |
4 | 133312210010012223 |
5 | 1030021030421303 |
6 | 23413435044203 |
7 | 2320354163226 |
oct | 376644040653 |
9 | 107246004353 |
10 | 34201420203 |
11 | 135608a0235 |
12 | 6765ba0663 |
13 | 32c094a362 |
14 | 19264305bd |
15 | d528d9203 |
hex | 7f69041ab |
34201420203 has 8 divisors (see below), whose sum is σ = 45650984400. Its totient is φ = 22776401408.
The previous prime is 34201420147. The next prime is 34201420241. The reversal of 34201420203 is 30202410243.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 34201420203 - 212 = 34201416107 is a prime.
It is a super-2 number, since 2×342014202032 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 34201420203.
It is not an unprimeable number, because it can be changed into a prime (34201424203) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6133098 + ... + 6138671.
It is an arithmetic number, because the mean of its divisors is an integer number (5706373050).
Almost surely, 234201420203 is an apocalyptic number.
34201420203 is a deficient number, since it is larger than the sum of its proper divisors (11449564197).
34201420203 is a wasteful number, since it uses less digits than its factorization.
34201420203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12272701.
The product of its (nonzero) digits is 1152, while the sum is 21.
Adding to 34201420203 its reverse (30202410243), we get a palindrome (64403830446).
The spelling of 34201420203 in words is "thirty-four billion, two hundred one million, four hundred twenty thousand, two hundred three".
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