3421004114003 has 4 divisors (see below), whose sum is σ = 3909718987440. Its totient is φ = 2932289240568.

The previous prime is 3421004113999. The next prime is 3421004114029. The reversal of 3421004114003 is 3004114001243.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3421004114003 - 2² = 3421004113999 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3421004114003.

It is not an unprimeable number, because it can be changed into a prime (3421004714003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244357436708 + ... + 244357436721.

It is an arithmetic number, because the mean of its divisors is an integer number (977429746860).

Almost surely, 2^{3421004114003} is an apocalyptic number.

3421004114003 is a deficient number, since it is larger than the sum of its proper divisors (488714873437).

3421004114003 is an equidigital number, since it uses as much as digits as its factorization.

3421004114003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 488714873436.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 3421004114003 its reverse (3004114001243), we get a palindrome (6425118115246).

The spelling of 3421004114003 in words is "three trillion, four hundred twenty-one billion, four million, one hundred fourteen thousand, three".