Base | Representation |
---|---|
bin | 110001110010011011010… |
… | …111101110000010111011 |
3 | 110010002020021221111210011 |
4 | 301302123113232002323 |
5 | 422024012031412021 |
6 | 11135434134002351 |
7 | 502121332500304 |
oct | 61623327560273 |
9 | 13102207844704 |
10 | 3421400654011 |
11 | 10aa00a52319a |
12 | 4731101a63b7 |
13 | 1ba837a93212 |
14 | bb84d3c37ab |
15 | 5dee9d2bde1 |
hex | 31c9b5ee0bb |
3421400654011 has 4 divisors (see below), whose sum is σ = 3425920338592. Its totient is φ = 3416880969432.
The previous prime is 3421400653969. The next prime is 3421400654149. The reversal of 3421400654011 is 1104560041243.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3421400654011 - 239 = 2871644840123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3421400657011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2259841155 + ... + 2259842668.
It is an arithmetic number, because the mean of its divisors is an integer number (856480084648).
Almost surely, 23421400654011 is an apocalyptic number.
3421400654011 is a deficient number, since it is larger than the sum of its proper divisors (4519684581).
3421400654011 is an equidigital number, since it uses as much as digits as its factorization.
3421400654011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4519684580.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 3421400654011 its reverse (1104560041243), we get a palindrome (4525960695254).
The spelling of 3421400654011 in words is "three trillion, four hundred twenty-one billion, four hundred million, six hundred fifty-four thousand, eleven".
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