Base | Representation |
---|---|
bin | 1001111101010011111… |
… | …10010110010001100011 |
3 | 1012201011022022200201100 |
4 | 10332221332112101203 |
5 | 21101212423010201 |
6 | 421103342005443 |
7 | 33501616643355 |
oct | 4765176262143 |
9 | 1181138280640 |
10 | 342154110051 |
11 | 12211a091086 |
12 | 5638a876883 |
13 | 2635a2660b0 |
14 | 127bb8430d5 |
15 | 8d7834a886 |
hex | 4fa9f96463 |
342154110051 has 12 divisors (see below), whose sum is σ = 532239726928. Its totient is φ = 210556375344.
The previous prime is 342154110049. The next prime is 342154110071. The reversal of 342154110051 is 150011451243.
342154110051 is a `hidden beast` number, since 34 + 215 + 411 + 0 + 0 + 5 + 1 = 666.
It is not a de Polignac number, because 342154110051 - 21 = 342154110049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 342154109997 and 342154110024.
It is not an unprimeable number, because it can be changed into a prime (342154110071) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1462196935 + ... + 1462197168.
Almost surely, 2342154110051 is an apocalyptic number.
342154110051 is a deficient number, since it is larger than the sum of its proper divisors (190085616877).
342154110051 is a wasteful number, since it uses less digits than its factorization.
342154110051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2924394122 (or 2924394119 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 342154110051 its reverse (150011451243), we get a palindrome (492165561294).
The spelling of 342154110051 in words is "three hundred forty-two billion, one hundred fifty-four million, one hundred ten thousand, fifty-one".
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