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3422312433 = 321920013523
BaseRepresentation
bin1100101111111100…
…0101011111110001
322211111200111002100
43023333011133301
524002102444213
61323332011013
7150544114161
oct31377053761
98744614070
103422312433
1114a6895a91
127b6160a69
13427038957
142467385a1
151506b3773
hexcbfc57f1

3422312433 has 12 divisors (see below), whose sum is σ = 5203516240. Its totient is φ = 2161460376.

The previous prime is 3422312401. The next prime is 3422312437. The reversal of 3422312433 is 3342132243.

3422312433 is a `hidden beast` number, since 3 + 4 + 223 + 1 + 2 + 433 = 666.

It is not a de Polignac number, because 3422312433 - 25 = 3422312401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3422312397 and 3422312406.

It is not an unprimeable number, because it can be changed into a prime (3422312437) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10006591 + ... + 10006932.

Almost surely, 23422312433 is an apocalyptic number.

It is an amenable number.

3422312433 is a deficient number, since it is larger than the sum of its proper divisors (1781203807).

3422312433 is a wasteful number, since it uses less digits than its factorization.

3422312433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20013548 (or 20013545 counting only the distinct ones).

The product of its digits is 10368, while the sum is 27.

The square root of 3422312433 is about 58500.5336129509. The cubic root of 3422312433 is about 1506.9767490054.

Adding to 3422312433 its reverse (3342132243), we get a palindrome (6764444676).

It can be divided in two parts, 34223 and 12433, that added together give a 6-th power (46656 = 66).

The spelling of 3422312433 in words is "three billion, four hundred twenty-two million, three hundred twelve thousand, four hundred thirty-three".

Divisors: 1 3 9 19 57 171 20013523 60040569 180121707 380256937 1140770811 3422312433