Base | Representation |
---|---|
bin | 1111100100000001111100… |
… | …00010000001001011000011 |
3 | 11111011201102102020122112101 |
4 | 13302000332002001023003 |
5 | 13441203400033143021 |
6 | 200441552503211231 |
7 | 10131361162240453 |
oct | 762007602011303 |
9 | 144151372218471 |
10 | 34223340131011 |
11 | a9a5045337799 |
12 | 3a08867446b17 |
13 | 1613329c25155 |
14 | 8645c0517d63 |
15 | 3e5363302a91 |
hex | 1f203e0812c3 |
34223340131011 has 8 divisors (see below), whose sum is σ = 34692632869104. Its totient is φ = 33754060362240.
The previous prime is 34223340131003. The next prime is 34223340131051. The reversal of 34223340131011 is 11013104332243.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 34223340131011 - 23 = 34223340131003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (34223340131051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2132100 + ... + 8543566.
It is an arithmetic number, because the mean of its divisors is an integer number (4336579108638).
Almost surely, 234223340131011 is an apocalyptic number.
34223340131011 is a deficient number, since it is larger than the sum of its proper divisors (469292738093).
34223340131011 is an equidigital number, since it uses as much as digits as its factorization.
34223340131011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6484661.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 34223340131011 its reverse (11013104332243), we get a palindrome (45236444463254).
The spelling of 34223340131011 in words is "thirty-four trillion, two hundred twenty-three billion, three hundred forty million, one hundred thirty-one thousand, eleven".
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