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3424051433 = 11311277403
BaseRepresentation
bin1100110000010110…
…1110000011101001
322211121221211112202
43030011232003221
524003024121213
61323433145545
7150564646145
oct31405560351
98747854482
103424051433
1114a7873580
127b685b2b5
134274c734a
14246a6c225
15150908b58
hexcc16e0e9

3424051433 has 4 divisors (see below), whose sum is σ = 3735328848. Its totient is φ = 3112774020.

The previous prime is 3424051369. The next prime is 3424051453. The reversal of 3424051433 is 3341504243.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3424051433 - 26 = 3424051369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3424051396 and 3424051405.

It is not an unprimeable number, because it can be changed into a prime (3424051453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155638691 + ... + 155638712.

It is an arithmetic number, because the mean of its divisors is an integer number (933832212).

Almost surely, 23424051433 is an apocalyptic number.

It is an amenable number.

3424051433 is a deficient number, since it is larger than the sum of its proper divisors (311277415).

3424051433 is a wasteful number, since it uses less digits than its factorization.

3424051433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 311277414.

The product of its (nonzero) digits is 17280, while the sum is 29.

The square root of 3424051433 is about 58515.3948375981. The cubic root of 3424051433 is about 1507.2319554741.

Adding to 3424051433 its reverse (3341504243), we get a palindrome (6765555676).

The spelling of 3424051433 in words is "three billion, four hundred twenty-four million, fifty-one thousand, four hundred thirty-three".

Divisors: 1 11 311277403 3424051433