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3425512115 = 5685102423
BaseRepresentation
bin1100110000101101…
…0010101010110011
322211201201001020002
43030023102222303
524003412341430
61323524340215
7150613241534
oct31413225263
98751631202
103425512115
1114a8680a53
127b724466b
134278b915c
14246d2c68b
15150ae6845
hexcc2d2ab3

3425512115 has 4 divisors (see below), whose sum is σ = 4110614544. Its totient is φ = 2740409688.

The previous prime is 3425512099. The next prime is 3425512163. The reversal of 3425512115 is 5112155243.

3425512115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3425512115 - 24 = 3425512099 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342551207 + ... + 342551216.

It is an arithmetic number, because the mean of its divisors is an integer number (1027653636).

Almost surely, 23425512115 is an apocalyptic number.

3425512115 is a deficient number, since it is larger than the sum of its proper divisors (685102429).

3425512115 is an equidigital number, since it uses as much as digits as its factorization.

3425512115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 685102428.

The product of its digits is 6000, while the sum is 29.

The square root of 3425512115 is about 58527.8746837778. The cubic root of 3425512115 is about 1507.4462506975.

Adding to 3425512115 its reverse (5112155243), we get a palindrome (8537667358).

The spelling of 3425512115 in words is "three billion, four hundred twenty-five million, five hundred twelve thousand, one hundred fifteen".

Divisors: 1 5 685102423 3425512115