Base | Representation |
---|---|
bin | 110001110111000101111… |
… | …101010000000101001011 |
3 | 110010120011102002220002011 |
4 | 301313011331100011023 |
5 | 422114241441244430 |
6 | 11142023203520351 |
7 | 502356431221216 |
oct | 61670575200513 |
9 | 13116142086064 |
10 | 3426410103115 |
11 | 11011501a447a |
12 | 4740899890b7 |
13 | 1bb15587c99c |
14 | bbba682477d |
15 | 5e1de9ed22a |
hex | 31dc5f5014b |
3426410103115 has 16 divisors (see below), whose sum is σ = 4249846782720. Its totient is φ = 2649254952960.
The previous prime is 3426410103101. The next prime is 3426410103133. The reversal of 3426410103115 is 5113010146243.
3426410103115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3426410103115 - 211 = 3426410101067 is a prime.
It is a super-3 number, since 3×34264101031153 (a number of 39 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14253934 + ... + 14492323.
It is an arithmetic number, because the mean of its divisors is an integer number (265615423920).
Almost surely, 23426410103115 is an apocalyptic number.
3426410103115 is a deficient number, since it is larger than the sum of its proper divisors (823436679605).
3426410103115 is a wasteful number, since it uses less digits than its factorization.
3426410103115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28747062.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 3426410103115 its reverse (5113010146243), we get a palindrome (8539420249358).
The spelling of 3426410103115 in words is "three trillion, four hundred twenty-six billion, four hundred ten million, one hundred three thousand, one hundred fifteen".
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