343310441 has 4 divisors (see below), whose sum is σ = 343350084. Its totient is φ = 343270800.

The previous prime is 343310423. The next prime is 343310447. The reversal of 343310441 is 144013343.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 144013343 = 281 ⋅512503.

It can be written as a sum of positive squares in 2 ways, for example, as 109098025 + 234212416 = 10445^2 + 15304^2 .

It is a cyclic number.

It is not a de Polignac number, because 343310441 - 2⁶ = 343310377 is a prime.

It is a super-2 number, since 2×343310441² = 235724117799228962, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (343310447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650 + ... + 26211.

It is an arithmetic number, because the mean of its divisors is an integer number (85837521).

Almost surely, 2^343310441 is an apocalyptic number.

It is an amenable number.

343310441 is a deficient number, since it is larger than the sum of its proper divisors (39643).

343310441 is a wasteful number, since it uses less digits than its factorization.

343310441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39642.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 343310441 is about 18528.6384011346. The cubic root of 343310441 is about 700.2111206731.

Adding to 343310441 its reverse (144013343), we get a palindrome (487323784).

The spelling of 343310441 in words is "three hundred forty-three million, three hundred ten thousand, four hundred forty-one".